Home » 2 students take an exam. The student with higher score will receive ‘Excellent’ student with the lower score – ‘Good’. Student 1’s score = x 1 + 1 .

2 students take an exam. The student with higher score will receive ‘Excellent’ student with the lower score – ‘Good’. Student 1’s score = x 1 + 1 .

2 students take an exam. The student with higher score will receive ‘Excellent’ student with the lower score – ‘Good’. Student 1’s score = x1 + 1.5, where x1 – amount of effort she invests in studying. (the greater the effort, the higher the score.). Student 2’s score = x2, where x2 is the amount of effort (measured in full days dedicated to studying) he exerts. Student 1 is the smarter of the two, i.e. if the amount of effort is fixed, he has a higher score by 1.5. Assume that x1 and x2 can take any integer value in 0, 1, 2, 3, 4, 5 . A student receives an award of 10 chocolate bars if she gets ‘Excellent’, and 8 chocolate bars if she gets ‘Good’. Both students’ invested effort of one study day has a negative effect on their well-being that corresponds to forgone consumption of one chocolate bar. Thus, the payoff to student i is (10 − xi) if she gets ‘Excellent’, and (8 − xi) if she gets ‘Good’, i = 1, 2.

Question:

1. What are the possible strategies of the students? What are their payoffs for each strategy combination? Represent this game in the normal (strategic) form.

2. Derive the strategies that survive the iterated elimination of strictly dominant strategies.

3. From the remaining strategies, which strategies are weakly dominated?

4. After the deletion of weakly dominated strategies, find a solution (equilibrium) of this game. What are the equilibrium efforts of the students?

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